Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Both [Ni(CO) 4 ] and [Ni(CN) 4 ] 2– are diamagnetic. The hybridisation of nickel in these complexes, respectively, are :
Text Solution
Verified by ExpertsThe correct answer is:
B
Ni (28)
1s 2 , 2s 2 2p 6 , 3s 2 3p 6 3d 8 , 4s 2
In [Ni(CO) 4 ], Ni is in zero oxidation state and CO being strong field ligand compels for paring of electrons.
So, [Ni(CO) 4 ] 
In [Ni (CN) 4 ] 2– , Ni is in +2 oxidation state and CN – being strong field ligand compels for paring of electrons.
So, [Ni(CN 4 ] 2– 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
When dimethyl glyoxime is added to the aqueous solution of nickel(II) chloride in presence of dilut…
Which kind of isomerism is exhibited by octahedral [Co(NH 3 ) 4 Br 2 ]Cl ?
The bond length in CO is 1.128 Å. What will be the bond length of CO in Fe(CO) 5 ?
NiCl 2 complex A
NiCl 2 complex B
A & B complexes have the co-ordination number 4.
(i) The IUPAC …
Among the following metal carbonyls, the C–O bond order is lowest in :
Match the complexes in Column-I with their properties listed in Column-II.
Column-IColumn-II(a) [Co…